(y+2)^2=3y+6

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Solution for (y+2)^2=3y+6 equation: 



(y+2)^2=3y+6

We move all terms to the left:

(y+2)^2-(3y+6)=0

We get rid of parentheses

(y+2)^2-3y-6=0

We add all the numbers together, and all the variables

-3y+(y+2)^2-6=0

We move all terms containing y to the left, all other terms to the right

-3y+(y+2)^2=6

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